bantu jawab dong mayan nih poinnya , 4 soal doank
tentukan
1.Volume tabung
2.Luas permukaan tabung
3.Volume kerucut
4.Luas permukaan kerucut
Jawaban:
1. 4.620 cm³
2. 1.628 cm²
3. 1.232 cm³
4. 704 cm²
Penjelasan dengan langkah-langkah:
1. V = πr² × t
= 22/7 × 7 cm × 7 cm × 30 cm
= 22 × 1 cm × 7 cm × 30 cm
= 22 cm × 7 cm × 30 cm
= 154 cm² × 30 cm
= 4.620 cm³
2. Lp = 2πr(r + t)
= 2 × 22/7 × 7 cm ( 7 cm + 30 cm)
= 44 × 1 cm × 37 cm
= 44 cm × 37 cm
= 1.628 cm²
3. V = ⅓ × la × t
= ⅓ × (22/7 × 7 cm × 7 cm) × 24 cm
= (22 × 1 cm × 7 cm) × 8 cm
= (22 cm × 7 cm) × 8 cm
= 154 cm² × 8 cm
= 1.232 cm³
4. Lp = πr(s + r)
= 22/7 × 7 cm ( 25 cm + 7 cm)
= 22 cm × 32 cm
= 704 cm²
nt :
t² = √(s² - r²)
= √(25² - 7²)
= √(625 - 49)
= √576
= 24
1. V = πr² × t
=> 22/7 × 7 cm × 7 cm × 30 cm
=> 22 × 1 cm × 7 cm × 30 cm
=> 22 cm × 7 cm × 30 cm
=> 154 cm² × 30 cm
=> 4.620 cm³
=========
2. Lp => 2πr(r + t)
=> 2 × 22/7 × 7 cm ( 7 cm + 30 cm)
=> 44 × 1 cm × 37 cm
=> 44 cm × 37 cm
=> 1.628 cm²
==========
3. V => ⅓ × la × t
=> ⅓ × (22/7 × 7 cm × 7 cm) × 24 cm
=> (22 × 1 cm × 7 cm) × 8 cm
=> (22 cm × 7 cm) × 8 cm
=> 154 cm² × 8 cm
=> 1.232 cm³
============
4. Lp => πr(s + r)
=> 22/7 × 7 cm ( 25 cm + 7 cm)
=> 22 cm × 32 cm
=> 704 cm²
Kesimpulan.
1) Volume tabung = 4.620 cm³
2) Luas permukaan tabung = 1.628 cm²
3) Volume kerucut = 1.232 cm³
4) Luas permukaan kerucut = 704 cm²
Penjelasan.
1) Volume tabung
=> V = π × r² × t
2) Luas permukaan tabung
=> 2 x Luas alas + Luas selimut
3) Volume kerucut
=> ⅓ × π × r × r × t.
4) Luas permukaan kerucut
=> πr (s + r).
ⒼⓄⓄⒹ ⓁⓊⒸⓀ
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